10y^2+27+5y=0

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Solution for 10y^2+27+5y=0 equation:


Simplifying
10y2 + 27 + 5y = 0

Reorder the terms:
27 + 5y + 10y2 = 0

Solving
27 + 5y + 10y2 = 0

Solving for variable 'y'.

Begin completing the square.  Divide all terms by
10 the coefficient of the squared term: 

Divide each side by '10'.
2.7 + 0.5y + y2 = 0

Move the constant term to the right:

Add '-2.7' to each side of the equation.
2.7 + 0.5y + -2.7 + y2 = 0 + -2.7

Reorder the terms:
2.7 + -2.7 + 0.5y + y2 = 0 + -2.7

Combine like terms: 2.7 + -2.7 = 0.0
0.0 + 0.5y + y2 = 0 + -2.7
0.5y + y2 = 0 + -2.7

Combine like terms: 0 + -2.7 = -2.7
0.5y + y2 = -2.7

The y term is 0.5y.  Take half its coefficient (0.25).
Square it (0.0625) and add it to both sides.

Add '0.0625' to each side of the equation.
0.5y + 0.0625 + y2 = -2.7 + 0.0625

Reorder the terms:
0.0625 + 0.5y + y2 = -2.7 + 0.0625

Combine like terms: -2.7 + 0.0625 = -2.6375
0.0625 + 0.5y + y2 = -2.6375

Factor a perfect square on the left side:
(y + 0.25)(y + 0.25) = -2.6375

Can't calculate square root of the right side.

The solution to this equation could not be determined.

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